Use the one-mean t-interval procedure with the sample mean, sample size, sample standard deviation, and confidence level given below to find a confidence interval for the mean of the population from which the sample was drawn.
sample mean=3.0 n=41 s=5.4 confidence level=90%
The 90% confidence interval about μ is ?? to ???
From the given information we want to find 90% confidence interval for population mean ( ).
Using minitab:
Step 1) Click on Stat>>>Basic Statistics >>1 sample t...
Select summarized data
Sample size: 41
Mean: 3.0
Standard deviation: 5.4
Step 2) Click on Option
Confidence level = 90
Alternative: Not equal
Then click on OK
Again Click on OK
Then we get the following output
From the above output the 90% confidence interval for is 1.580 to 4.420
Use the one-mean t-interval procedure with the sample mean, sample size, sample standard deviation, and confidence...
Use the one-mean t-interval procedure with the sample mean, sample size, sample standard deviation, and confidence level given below to find a confidence interval for the mean of the population from which the sample was drawn. x̄=4.0 n=61 s=6.1 confidence level =99% The 99% confidence interval about μ is ??? to ??? (Round to four decimal places as needed.)
Use the one-mean t-interval procedure with the sample mean, sample size, sample standard deviation, and confidence level given below to find a confidence interval for the mean of the population from which the sample was drawn. x overbarxequals=2.0 nequals=51 sequals=4.5 confidence levelequals=95% Click here to view page 1 of the table of critical values for the t distribution. LOADING... Click here to view page 2 of the table of critical values for the t distribution. LOADING... The 95% confidence interval...
A sample mean, sample size, population standard deviation, and confidence level are provided. Use this information to complete parts (a) through (c) below. x overbarx equals=25, n equals=38, sigma σ equals=4 confidence level equals=95% Click here to view page 1 of the standard normal distribution table. LOADING... Click here to view page 2 of the standard normal distribution table. LOADING... . Use the one-mean z-interval procedure to find a confidence interval for the mean of the population from which the...
Part B A sample mean, sample size, population standard deviation, and confidence level are provided. Use this information to complete parts (a) through (c) below. x=52, n = 13,0-6, confidence level = 99% Click here to view page 1 of the standard normal distribution table. Click here to view page 2 of the standard normal distribution table. a. Use the one mean z-interval procedure to find a confidence interval for the mean of the population from which the sample was...
A sample mean, sample size, population standard deviation, and confidence level are provided. Use this information to complete parts (a) through (c) x = 33, n = 25, C = 6, confidence level = 90% Click here to view page 1 of the standard normal distribution table. Click here to view page 2 of the standard normal distribution table a. Use the one-mean z-interval procedure to find a confidence interval for the mean of the population from which the sample...
use the one mean t interval procedure to find a confidence level for the mean of the population. x bar= 50, n=16, s=5 and the confidence level is 99%
A sample mean, sample standard deviation, and sample size are given. Use the one-mean t-test to perform the required hypothesis test about the mean, μ, of the population from which the sample was drawn. Use the critical-value approach. 7. x-20.8, s-7.3>, n = 11, Ho: μ = 18.7, Ha: μ # 18.7, α = 0.05 a. Test statistic: t = 0.95. Critical values: ±1.96. Reject Ho. There is sufficient evidence to b. Test statistic: 0.95. Critical values: t = ±2.201....
92.19-T Question Help A simple random sample of size n is drawn from a population that is normally distributed. The sample mean, x, is found to be 18.3, and the sample standard deviation s, is found to be 5.6. (a) Construct a 90% confidence interval about if the sample size, n, is 31. (b) Construct a 90% confidence interval about μ if the sample size, n' is 61 . How does increasing the sample size affect the margin of error,...
Here is an example with steps you can follow: sample size n=9, sample mean=80, sample standard deviation s=25 (population standard deviation is not known) Estimate confidence interval for population mean with confidence level 90%. Confidence Interval = Sample Mean ± Margin of Error Margin of Error = (t-value)×s/√n t-value should be taken from Appendix Table IV. For n=9 df=n-1=9-1=8 For Confidence Level 90% a = 1 - 0.90 = 0.10, a/2 = 0.10/2 = 0.05 So, we are looking for...
A sample mean, sample size, and population standard deviation are given. Use the one-mean z-test to perform the required hypothesis test at the given significance level. Use the P-value approach. x̄ = 259, n = 15, σ = 19, H 0: μ = 250, Ha : μ > 250, α = 0.01