Determine the pH change when 0.042 mol Hl is added to 1.00L of a buffer solution...

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Question

Answer 1

Answer #1

initially

.pH = pKa + log [CN^-] / [HCN]

pKa of HCN = 9.2.

pH = 9.2 + log [0.206] / [0.392]

pH = 8.92

after 0.042 mol HI added

[HCN] = 0.392 + 0.042 = 0.434 M

[CN^-] = 0.206 - 0.042 = 0.164 M

pH = 9.2 + log [0.164]/[0.434]

pH = 8.78

pH change = 8.78 - 8.92 = - 0.14.

negative sign represent decreasing pH value

Answer 2

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