Question

I need clarification on R studio code. Given the below table, what is Y ~ A + B + A*B? Is it the same as Y~A*B?

Syntax Model Comments Y~ A Straight-line with an implicit y- intercept Straight-line with no y-intercept that is, a fit forced through (0.0 Polynomial model; note that the identity function I() allows terms in the model to include normal mathematical symbols A first-order model in A and B without interaction terms A model containing only first-order nteractions between A and B Y A B Y A:B Y-po-B1A+ β2B+ β3AB | A full first-order model with a term; an equivalent code is Y-A +B+ A:B Y ~ (A+ B + C)/2 | Y-pot ß1A + β2B+ β3C+ | A model including all first-order effects and interactions up to the n order, where n is given by ( ) An equivalent code in this case is

Answer 1

Yes it is same i have it prove by example here i have taken data of mtcars and proved it .

## we have to clarification of Y-A+B+(A"B) Is same or not Y=(A"B) ### Here i have taken one data set is related to cars and i assume Y is mpg as dependent ## And A is first And B is second independent variable library(dplyr) data (mtcars) mtcars class (mtcars) d-mtcars View(mtcars) y-dSmpg A-d$disp B-d$hp regi-1m(y A+B+(A B)) regl summary (reg1) reg2-1m(y(A B)) reg2 summary (reg2) ## Conc1suion : here both regi is Y-A+8+ (A"B) įs same as reg2 is Y (A*B) it can be get ## of summary same for both regression is same hence both is same.