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The position of a squirrel running in a park is given by r = [(0.280 m/s)t + (0.0360 m/s2)t2] (0.0190 m/s)tj

3. At 4.48 s , how far is the squirrel from its initial position?

4. At 4.48 s , what is the magnitude of the squirrel's velocity?

5. At 4.48 s , what is the direction (in degrees counterclockwise from +x-axis) of the squirrel's velocity?

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