Question

Use these rules to work out the following problem: A U-shaped tube is connected to a box at one end and open to the air at the other end. The box is full of gas at pressure pgas, and the tube is filled with mercury of density 1.36×104 kg/m3 . When the liquid in the tube reaches static equilibrium, the mercury column is h1 = 11.5 cm high in the left arm and h2 = 5.00 cm high in the right arm, as shown in the figure.(Figure 1) What is the gas pressure pgas inside the box?

A. Assume patmos=1.00atm. What is the gas pressure pgas?

Answer 1

Consider the following data Height, h11.5 cm Density of mercury, p 101300 Pa 1.36x101 kg/m3 Calculate the height above given point. h-h-h -11.5-5 6.5 cm Consider the hydrostatic pressure equation. gasa Here, Pais the pressure of gas, Pt is atmospheric pressure, g is acceleration due to gravity and h is change in height Substitute the values in equation (1). 101300-1.36x10+,9.8x6.5 x10-2Pa -92636.8 Pa Hence, the gas pressure is 926368 Pa