When a 60-kg boy sits at rest on a trampoline, it says 0.10 m at the...
When a 60-kg boy sits at rest on a trampoline, it says 0.10 m at the center.
a. What is the effective spring constant for the trampoline?
b. The trampoline is pulled downward an extra 0.050 m by a strap sewed under the center of the trampoline. When the strap is released, what are the energy and frequency of the trampoline?
Homework Answers
a)
Here force due to gravity is balanced by spring restoring force
mg =Kx
K=mg/x =60*9.81/0.1
K=5886 N/m
b)
Energy of the trampoline
E=(1/2)Kx2 = (1/2)*5886*0.052
E=7.358 J
frequency
f=(1/2pi)sqrt[K/m]
f=(1/2pi)sqrt[5886/60]
f=1.576 Hz
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