Question

Consider the reaction 2H2S(g)+302(g)2H20)+2SO2(g) Based upon the stoichiometry of the reaction the sign of AS°Txn should be a

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Answer #1

Sol:-Sign of the S0rxn will be negative because in products 2 moles of liquid and 2 moles of gas is formed from 4 moles of gases.

we know that

∆Sorxn =  ∑Soproducts -   ∑Soreactants

∆Sorxn = [2 X So of H2O(l) + 2 X So of SO2(g)] - [ 2 X So of H2S(g) +   3 X So of O2(g)]

∆Sorxn = [2 X 70.0 J/mol.K + 2 X 248.2 J/mol.K ] - [2 X 205.8 J/mol.K + 3 X 110.9 J/mol.K ]

∆Sorxn = 636.4 J/mol.K - 744.3 J/mol.K

∆Sorxn = -107.9  J/mol.K

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