Sample Size: n = 5
First observation (x1) : 49
Second observation (x2) : 52
Third observation (x3) : 34
Fourth observation (x4) : 85
Fifth observation (x5) : 43
Sum ( Σx ) : 263
Sum of squares ( Σx2 ) : 15335
What is the lower quartile (Q1) of your sample data?
Answer
For calculating the value of lower quartile or first quartile, first we need to arrange the given data in ascending order
So, new order becomes
34, 43, 49, 52, 85
We have odd number of observations, so median will be the center
So,median = 49 (because its in the center)
Now, we have lower half = 34, 43 and upper half= 52, 85
Now, we have only two observations in lower half, so lower quartile would be the mean or average of these two observations
So, lower quartile = (34+43)/2 = (77/2) = 38.5
Thus, required lower quartile is 38.5
Sample Size: n = 5 First observation (x1) : 49 Second observation (x2) : 52 Third...
Sample Size: n = 5 First observation (x1) : 49 Second observation (x2) : 52 Third observation (x3) : 34 Fourth observation (x4) : 85 Fifth observation (x5) : 43 Sum ( Σx ) : 263 Sum of squares ( Σx2 ) : 15335 What is the variance of your sample data?
WHat is the lower quartile of this sample data? Sample Size: n-5 First observation (XT) : Гб Second observation (x2) : 28 Third observation (x3) :43 Ëourth Observation (X4) : бг Fifth observation (x5): 52 Sum (2x) 200 Sum of squares (2x2): 9314
What is the variance of this data set? Sample Size: n-5 First observation (XT) : Гб Second observation (x2) : 28 Third observation (x3) :43 Ëourth Observation (X4) : бг Fifth observation (x5): 52 Sum (2x) 200 Sum of squares (2x2): 9314
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