Solution :-
We know that
Force F = (1/4πε0)* q1 * q2 / r2
a. F=9.0×109×(-5.71× 10-16 )×(- 5.71×10-16 )/(0.758 × 10-2)2
F = 5.107×10-17 N( Repulsive)
b. By, quantization of charge principle
q = n×e
-5.71×10-16 = n×(-1.6×10-19)
n = (5.71×10-16 / 1.6×10-19 ) = 3568.75
Each drop has 3569 excess electrons
Chapter 21, Problem 024 Two tiny, spherical water drops, with identical charges of-5.71 × 10-16 C,...
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