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Two 4.00-g spheres are suspended by 22.0-cm-long light strings (see the figure). A uniform electric field is applied in the x

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Given that :- mass = 4.000 Length = 22cm = -3.500*10-8 22 = +3.50 * 10 de 0 = 12 2 JA 25 from Newtons and law, o mg +7 + FDistance b/w two charges: 8=22 sino = 2*(0.22m) (sin 12 ) 20.091m. the force by field intensity coulombs law; x: F = Ffueld

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