Question

we did synthesis of 4'-propoxyacetophenone:Analysis using Infrared Spectroscopy. how would i find the LR and the theoretical yield?

Cuperiment Five: Synthesis of 4’-Propoxyacetophenone: Analysis using Infrared Spectroscopy. NaOH TBABr HO

Answer 1

molecular weight (considering actually used data )

4-hydroxyacetophenone 136.15 g/mol So the number of mol use in the reaction ( 1.01g/136.15 g/mol ) = 0.00741 mol

1-Bromopropane 122.99 g/mol So the number of mol use in the reaction ( 1.8 ml * 1.35 g/ml) /122.99 g/mol

(Density: 1.35 g/ml ) = 0.0197 mol

As no of mol of 4-hydroxyacetophenone < no of mol of  1-Bromopropane And As the molar ratio of the reactants is 1:1

so 4-hydroxyacetophenone is the limiting reagent.

the molecular weight of the product is 178.23 g/mol

if our limiting reagent (i.e. 4-hydroxy acetophenone) is fully converted to the product then that yield will be the theoretical yield.

0.00741 mol of 4-hydroxy acetophenone will convert to the product then the amount of the product will be

(0.00741 mol * 178.23 g/mol ) = 1.32 g

the theoretical yield of the reaction is 1.32 g.