Question

The index of refraction for a particular silica fiber is n=1.44. If you shine light on the fiber at an angle of $\Theta$i = 38 degrees from the air, what would the refracted angle be? How would your answer change if the diamond were immersed in water (that is, the light was coming from a region with n=1.33)?

Answer 1

For n_1 = 1 air n_2 = 1.44 theta_i = 38 degree Snell�s law n_1 sin theta_i = n_2 sin theta_r (1)sin 38 = (1.44) sin theta_r sin theta_r = 0.42754 theta_r = 25.311 degree Now in water (1.33) sin 38 degree = (1.44) sin theta_r sin theta_r = 0.56863 theta_r = 34. 6548 degree