Question

006 (part 1 of 2) 10.0 points A ladder rests against a vertical wall. There is no friction between the wall and the ladder. The coefficient of static friction between the ladder and the ground is μ-0.581

Answer 1

We can get the equation by translation and rotational equilibrium as solved below

f = Force el friction, between the ladder the ground f_w = Normal force on the ladder due to wall theta = angle between the ladder and ground N = Normal force on the ladder due to ground w = weight of ladder l = length of ladder A_1 = > F_w = f A_2 = > F_w sin theta = f B_1 = > W/2 = N B_2 = > N = w C_1 = > l F_w sin theta = 2 F_w cos theta C_2 = l F_w sin theta = l w cos theta C_3 = l F_w sin theta = 1/2 l w cos theta correct equations are the Rod is in equilibrium so in vertical direction and in horizontal direction Net force should be zero in vertical direction N = w in Horizontal direction f = fw Now for Rotational equilibrium torque about point A must be zero so F_w l sin theta - w l/2 sin theta = 0