Question

tx=1 m, y = 2 m. A point charge of -6 pC is located at x 3 m, y =-2 m. A second point charge of 12 C is located at (a) Find the magnitude and direction of the electric field at x = -1 m, y = 0. | N/C Reset Enter Help 12.5 points] 1 attempt (s) made (maximum allowed for credit [after that, multiply credit by 0.5 up to 10 attempts 8.4e3 NO 5) (counterclockwise from plus x axis) 12.5 points) 1 attempt (s) made (maximum allowed for credit 5) Reset Enter (after that, multiply credit by 0.5 up to 10 attempts 254,8 NO (b) Calculate the magnitude and direction of the force on an electron at xr= -1 m, y 0 Enter 2.5 points) 0 attempt(s) made (maximum allowed for credit (after that, multiply credit by 0.5 up to 10 attempts 5) * (counterclockwise from plus x axis) Enter (25 points) 0 attempt(s) made (maximum allowed for credit (after that, multiply credit by 0.5 up to 10 attempts 5)

Answer 1

1 3(0-(-2))

-4)i (2)

ri25m

5 =(-1 -1)i +(0-2)

-2i-2j

= 2/2m r2

kQ2 1+ '2 kQ1 E

a.)

E 22.114 103-0.264i 0.398j 0.4776

22.114 103N/C E =

56.45

b.)

$\vec{F}=q_{e}\vec{E}$

F =1.6 10-19 22.114 1030.264 0.398j 0.4776

$\vec{F}=-35.38*10^{-16}[\frac{-0.264 \hat{i}-0.398 \hat{j}}{0.4776}] {N}$

35.38 10-16 N

$\theta=180$$\theta=180^o+56.45^o=236.45^o$