A student carefully pipets 25.0 mL of 0.525 M NaOH into a test tube. She places...

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Answer 1

Answer #1

The moles of acid and base in the beakers are calculated:

n NaOH = M * V = 0.525 M * 0.025 L = 0.0131 mol

n HCl = 0.355 M * 0.075 L = 0.0266 mol

There is more moles of acid than base, so the resulting solution is acid.

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Answer 2

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