A large positively-charged object with charge q = 3.25 ?C is brought near a negatively-charged plastic ball suspended from a string of negligible mass. The suspended ball has a charge of q
force on the suspended ball, F = k q1 q2 / r2
= 9 * 109 * 3.25 * 10-6 * 54.3 * 10-9 / 0.2152
= 0.0344 N
let t be the rension in the string.
then T sin theta = 0.0344 ---------------------(1)
T cos theta = 16.5 * 10-3 * 9.81 = 0.162 N ----------------------(2)
dividing eqn(1) by eqn (2)
tan theta = 0.212
theta = 11.97 degree
A large positively-charged object with charge q = 3.25 ?C is brought near a negatively-charged plastic...
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