Question

3.115 points) a) If a beam of the a beam of light strikes the face of the beam emerge from the right prism? ancidence show, b) At what angle will the light undergo total internal reflection inside of the left prim? (Critical angel c) At what angle of incidence with the left prism would the beam undergo total internal reflection at the interface of the prisms?

Answer 1

(a) Using snells law n sin 45 n2 sin 0 sin 45 sin п, 1.6sin 45 1.4 0.808 sin(0.808) -53.910 x=0-45 tl =53.91-45 =8.90 The angle of incidence for the prism is, Ө, — х 8.90 Using snells law 1.4sin 8.9 1.0sin 1.4sin 8.9° -1 0= sin 1.0 =12.50 (b) The crictical anglefor internal reflection is, п, sin e п 1 sin 45 п 0 1 п- 0.707 = 1.41

(c) prism() n1(air) n,1.6 prism (2) n-1.4 450 For prism (1), prism (2) interface, 1.6sin 1.4sin 90° 1.4 sin 1.6 1.4 1.6 =610 We can draw the daigram as follows n 1.6 BOr 45 45 From triangle Z0= 45° ZB = 180° -(ZO+ ZA) = 180° - (45+29) =106 90+, 106 e, =160 Using Snells law for air prism (1) interface n sin n sin , 1sin 1.6sin 16 e=sin1(0.441) 26.20