a 73.6g sample of aluminum is heated to 95.0 degrees and dropped into 100g of water...
. A 150.0 g sample of a Metal was heated to 95.0°C. When the hot metal was placed into 100.0 g of water in a calorimeter, the temperature of the water increased from 20.0°C to 35.0°C. The specific heat of water is 4.184 J/g °C. a) What is the specific heat of the metal? Kb) What would the final temperature be if the mass of water was 150.0 q?
200 g of an unknown metal is heated to 90.0 degrees C, then dropped into 50.0 g of water at 20.0 degrees C in an insulated container. The water temperature rises within a few seconds to 27.7 degrees C, then changes no further. Identify the metal.
A metal sample weighing 24.000 g is heated to 100.0 degrees celsius and then transferred into a calorimeter containing 30.0 mL of water at a temperature of 22.8 degrees celsius. If the specific heat of the metal is 0.105 J/g*C, what is the final temperature of the metal sample plus water?
aluminum chloride has a solubility of 48.6 grams per 100g of water at 80 degrees Celsius what is the maximum possible molality of an aqueous AlCl3 solution at 80 degrees Celsius S. Aluminum chloride has a solubility of 48.6 grams per 100 g of water at 80°C. What is the maximum possible molality of an aqueous AICl3 solution at 80°C? Show your work.
A 750 g block of copper is heated to 250 degrees C. It is placed in a 350 g aluminum vessel that contains 200 g of water at 5.00 degrees C. What is the final temperature of the copper, water, and aluminum vessel? Specific heat of copper = 0.093 cal/g C degrees Specific heat of aluminum = 0.215 cal/g C degrees Specific heat for water = 1.0 cal/g C degrees
A 3.00-g sample of aluminum pellets (specific heat capacity = 0.89 J/°C·g) and a 11.00-g sample of iron pellets (specific heat capacity = 0.45 J/°C·g) are heated to 100.0 °C. The mixture of hot iron and aluminum is then dropped into 73.8 g water at 22.0 °C. Calculate the final temperature of the metal and water mixture, assuming no heat loss to the surroundings. Please be super specific on how you get to each step!
A metal alloy bolt is initially at 100.0 degrees * C . It is dropped into a coffee cup calonmater Containing 50.0 g of water at a temperature of 20.0*C. After stirring, the final temperature both bolt and water is 25.0 degrees * C . Assuming no heat losses, and that the specific heat capacity of water is 4.18J / (g - K) what is the heat capacity of the boltin nd / K ? QUESTION 5 A metal loy...
how much heat is needed to heat 100g of water initially at room temperature (20 degrees C) to a final temperature of 70 degrees C. The specific heat of water is 1.p cal/g×degrees C.
7. A 100g mass of tungsten at 100 degrees C is placed in 200 mL of water at 20 degrees C. The mixture reaches equilibrium at 21.6 degrees C. Calculate the specific heat of tungsten. Ok, I tried working it out but I got q= 100g x 4.186 j/g*degrees C * (21.6 degrees C- 20.0 degrees C) which equals to 1.6. So q= 100g * 4.186 j/g*deg C * 1.6 I got a very high number. I am stuck what...
A 3.00-g sample of aluminum pellets (specific heat capacity=0.89 J/°C g) and a 18.50-g sample of iron pellets (specific heat capacity = 0.45 J/°C-g) are heated to 100.0 °C. The mixture of hot iron and aluminum is then dropped into 77.4 g water at 22.0 °C. Calculate the final temperature of the metal and water mixture, assuming no heat loss to the surroundings. Final temperature = 20.23 °C An error has been detected in your answer. Check for typos. miscalculations...