A motorcycle traveling at a speed of 36.0 mi/h needs a minimum of 41.0 ft to stop. If the same motorcycle is traveling 68.0 mi/h, determine its minimum stopping distance (in ft), assuming the same rate of acceleration.
here,
the initial speed of motorcycle , u1 = 36 mi/h
the initial minimum distance , s1 = 41 ft
when ,
the initial speed of motorcycle , u2 = 68 mi/h
the initial minimum distance is s2
final speed is zero
using third equation of motion
v^2 - u^2 = 2 * a * s
as v = 0
- u^2 = 2 * a * s
so,
s2/s1 = u2^2 /u1^2
s2 = 41 * 68^2 /36^2
s2 = 146.3 ft
the minimum distance is 146.3 ft
A motorcycle traveling at a speed of 36.0 mi/h needs a minimum of 41.0 ft to...
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