10. In a past election, the voter turnout was 73%. In a survey, 878 subjects were asked if they voted in the election.
a. Find the mean and standard deviation for the numbers of voters in groups of 878.
b. In the survey of 878 people, 660 said that they voted in the election. Is this result consistent with the turnout, or is this result unlikely to occur with a turnout of 73%? Why or why not?
c. Based on these results, does it appear that accurate voting results can be obtained by asking voters how they acted?
10. In a past election, the voter turnout was 73%. In a survey, 878 subjects were...
in a past election, the voter turnout was 62%. In a survey, 806 subjects were asked if they voted in the election. a. Find the mean and standard deviation for the numbers of voters in groups of 806. b. In the survey of 806 people, 498 said that they voted in the election. Is this result consistent with the turnout, or is this result unlikely to occur with a turnout of 62%? Why or why not? c. Based on these...
In a past election, the voter turnout was 69%. In a survey, 934 subjects were asked if they voted in the election. a. Find the mean and standard deviation for the numbers of voters in groups of 934. b. In the survey of 934 people, 695 said that they voted in the election. Is this result consistent with the turnout, or is this result unlikely to occur with a turnout of 69%? Why or why not? c. Based on these...
In a past election, the voter turnout was 66%. In a survey, 1121 subjects were asked if they voted in the election. a. Find the mean and standard deviation for the numbers of voters in groups of 1121. b. In the survey of 1121 people, 707 said that they voted in the election. Is this result consistent with the turnout, or is this result unlikely to occur with a turnout of 66%? Why or why not? c. Based on these...
In a past presidential election, the actual voter turnout was 62%. In a survey, 882 subjects were asked if they voted in the presidential election. Find the mean and standard deviation for the numbers of actual voters in groups of 882. (Round answer to one decimal place.) = 546.84 (Round answer to two decimal places.) 14.42 = Give the interval of usual values for the number of voters in groups of 882. (Enter answer as an interval using square-brackets only...
This Question: 1 pt of 13 (4 This Quiz: 13 pts possi and standard deviation for the In a past election, the voter turnout was 79%, in a s numbers of voters in groups of 931. b. In the survey of 931 people, 693 said that they voted in the election. Is this result u kely to occur with a tumou of 79%? why or why not? c ased on these r results, does it appear that accurate voting results...
Public participation in election processes is a key to democracy. Let’s examine voter turnout in the 2010 November elections by educational level. Educational Level Number That Voted (in thousands) Less than high school graduate 29,837 High school graduate or GED 70,998 Some college or associate’s degree 65,321 Bachelor’s degree 41,703 Advanced degree 21,831 Find the 20th and 80th percentile for the number of voters. Write a few sentences explaining why the results from a) need to be cautiously interpreted. (Hint:...
In a survey of 1145 people, 862 people said they voted in a recent presidential election. Voting records show that 73% of eligible voters actually did vote. Given that 73% of eligible voters actually did vote, (a) find the probability that among 1145 randomly selected voters, at least 862 actually did vote. (b) What do the results from part (a) suggest? (a) P(X>862)=
In a survey of 1127 people, 739 people said they voted in a recent presidential election. Voting records show that 63% of eligible voters actually did vote. Given that 63% of eligible voters actually did vote, (a) find the probability that among 1127 randomly selected voters, at least 739 actually did vote. (b) What do the results from part (a) suggest? (a) P(x≥739) = b) What does the result from part (a) suggest? A.People are being honest because the probability...
In a survey of 1466 people, 1049 people said they voted in a recent presidential election. Voting records show that 69% of eligible voters actually did vote. Given that 69% of eligible voters actually did vote, (a) find the probability that among 1466 randomly selected voters, at least 1049 actually did vote. (b) What do the results from part (a) suggest? (a) P(X2 1049) = (Round to four decimal places as needed.) (b) What does the result from part (a)...
all answers ! 5. The actual time it takes to cook a ten-pound turkey is a normally distributed. Suppose that a random sample of 20 ten pound turkeys is taken with a sample mean of 2.9 hours and a sample standard deviation of 0.24 hours. Calculate a 95% confidence interval for the average cooking time of a ten pound turkey. 6. A recent Gallop poll showed Trump's approval rating 40% with a margin or error of 3%. a) Find the...