here,
mass of man , m1 = 90 kg
x = 2.1 m
a)
the approximate moment of torque due to the weight of man , T1 = m1 * g * x
T1 = 90 * 9.81 * 2.1 N.m = 1854.1 N.m
b)
let the distance of Woman from the pivot point be s
equating the torques
T1 = T2
T1 = m2 * g * s * sin(45)
1854.1 = 60 * 9.81 * s * sin(45)
solving for s
s = 4.45 m
the distance of woman is 4.45 m
Question 4 5 pts The following scenario shows a woman military pressing a lever that is...
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