Question

Part A A balloon is floating around outside your window. The temperature outside is 17 °C. and the air pressure is 0.700 atm Your neighbor, who released the balloon, tells you that he filled it with 4.00 moles of gas: What is the volume of gas inside this balloon? Express your answer to three significant figures and include the appropriate units. View Available Hint(s) TUA Vballoon = Value Units Submit Part B A 18.0 L gas cylinder is filled with 0.00 moles of ges. The tank is stored at 55 °C. What is the pressure in the tenk? Express your answer to three significant figures and include the appropriate units. View Available Hints) Value Units Submit

Answer 1

Part A Given that Temperature T = 12°C = 273 +17 k = 290k Pressure of air, P = 0.700 atm no. of moles of gas = 4 mo We have from ideal gas equation PV = nRT = nRT here R=0.0821 Lahm mot kt Substituting the values, we get - 4 mores x 0.0821 Latm mot fx2904 0.700 am 95.236 L 0.700 136 L v = Thus, volume = 136 L

Part B Given that Volume, U=182 no. of mors of gas, n=9 mo! Temperature, I = 55°c = 273+55k = 328k Pressure = ? R=0.0821 Lank-mol We have PV = nRT on P = MRT 0 x 0.0821 Cam K not x 328k amo 184 242.35 am 18 P = 13.4 am Pressure = 13.4 atin .

Part C Given that Volume, V = 2802 W T = 1255° c - 273 + 12,55 k - 1628K Pressure p = 1.07s ahon R = 0.0821 Latm mal kl n ? We have from ideal PV = nRT gas equation o na PV RT Substituting the values, we get n. 1.075 atrox 260x 0.0821 Xaften med ly x 16284 301 moles moles 122.65 = 2,25 miles m. of males of gas = 2,25 miles 1

Part D Gwen that volume, V = 102 no. of moles, n= 6.80 moles Pressure, P = 4.60 ahm Temperature ,T=?. R = 0.081 Lammol kl We have from ideal gas equation PU=nRT Substituting the values, we get S T = 4060am x TOL - 1.60 atm x 100 6.80 m3u x 0.08 21 X atm mot kl 0558 - 82.4K Temperaturo ,I = 82.4k