3a. the following diagram shows a tidally locked planet in orbit around sun, we can see that the angular rotation vector of the planet and the angular revolution vecotr of the planet around the sun both point in the same direction and hence the prograde nature of rotation
b. if it rotated in the reterograde direction, it would still
complete on rotation in one year, and one revolution in one
year
but the hemisphere facing the sun intiially, will face
sun again after half an year and again after one full year, so we
will have 2 days and 2 nights per year ( revolution)
c. for 365.24 solar days
in prograde motion, earth must revolve n times
(approximately) for there to be so many days
now sideareal rotation period = 23 hours and 56
minutes
hence
n*(23 hours 56 minutes) = 365.24*24 hours
hence
n = 366.25738 times
d. hence, general formula relating length of solar day, Ts
sideareal day, T'
n*T' = y*Ts
where y is length of mean solar year and n is numebr
of revolutions made per year
using this and data from internet we can derive the
day length in various planets to be as under
Mercury = 176 earth days
Venus = 116.75 days ( for reterograde rotation)
Mars = 24 houts 40 minutes
3a. A planet that keeps the same hemisphere pointed towards the Sun must rotate once per...
3a. A planet that keeps the same hemisphere pointed towards the Sun must rotate once per orbit in the prograde direction. Draw a diagram to demonstrate this fact. The rotational period in an inertial frame, the sidereal day, for such a planet is equal to the orbital period, the length of the solar day on such a planet is infinite (this is known as being tidally locked). b. If a planet rotated once per orbit in the retrograde direction, how...
> May I have the name of the textbook?
jasonli99 Sat, Feb 19, 2022 6:46 AM