Question

An object is placed $LaTeX: s_o=15\,\text{cm}$ so=15cm away from a convex mirror of focal length $LaTeX: f=-30\,\text{cm}$ f=−30cm.
Answer the following questions.

1. What is the distance of the image from the lens?

2. The image is:

virtual, right-side-up, and in front of the mirror

virtual, right-side-up, and behind the mirror

real, up-side-down, and behind the mirror

real, up-side-down, and in front of the mirror

image does not form

3. What is the magnification of the image?

Answer 1

Given object distance u = 15 cm Focal length (f) = -30 cm Now we know that 1/v - 1/u = 1/f so, 1/v = -1/30 + 1/15 1/v = -1 + 2/30 1/v = 1/30 therefore v = 30 cm b) Image is positive, thus the image is formed behind the mirror, thus virtual and errect Now magnification, m = -v/u implies -30/15 implies - 2