Question

1. Complete a frequency distribution tally sheet and a histogram of the measurement data given below in table 1-1 Table 1-1 Finished length of a shaft being faced on an engine lathe. Specifications: 4520.5 mm 45.0 45.1 45.5 45.0 45.5 45.5 45.7 45.5 45.5 45.0 45.7 45.3 45.6 45.0 45.0 45.0 45.6 45.0 45.6 45.7 45.6 45.5 45.4 45.5 45.4 45.1 45.2 45.0 45.0 45.1 45.3 45.3 45.4 45.6 45.4 45.6 45.2 45.6 45.6 45.0 45.8 45.3 45.2 45.4 45.3 45.6 45.4 45.4 45.1 45.4 Note You may use a computer program to draw the histogram of the data and then insert it in your word file if you have knowledge on how to complete it. If not, completing the histogram by hand and scanning it to the computer is sufficient. Just ensure that it is neat and legible. On your histogram plot: Draw the lines that indicate the process capability Draw the lines that show the LSL and USL Plot a line that shows the nominal value (45.0 mm) Plot a line that shows the average of the process output a. Is the process acceptable? Why? 1b. What adjustments, if any, would you make to this process to improve its performance?

Answer 1

shcet For fequency distn bution tally in the Mark the smalle st and largest Value data 45.0 PS. 5.5 45.0 45.5 45.5 45.745.5 45.o 45.5 45.7 45.6 45. 0 4S.6 4 5.6 45.子 45-3 45. D 45.0 45.D 45.0 45.4 45.5 45-) 4S.0 45.2 45.6 45.4 45. 45.5 45.6 45.0 45.4 5.6 45.3 45.6 45.2 45.4 45.3 45.6 45.4 45.3 45.3 45.4 45.2 45.6 45.445.4 45.1 4S.8 Range of 45.8 45.0 measuremenD O.8 no.of observations to take 5 to 7intervals a s are o De have So

Midpoint |Frequenc Tnterva Boundaries Telly 44.45 44. 44.5 44.45 44.55 44.65 44.7h.55 - 44.75 44. 44.85 44.9 75- 44.95 t5.05 45.o 45. 44.95 45.15 14 45.15 45.35 45.25 45.2 45.3 & - 45.55 L 15 45.5 4S.35 45.45 4S.745.55 - 45.75| L Hr 45.65 45.6 45.945.78 45.95 45.7545.8 50 need of first 3 intarvals There is It is just taken for shouing histogram ho LSL in n CY

LSL=44.50 Nominal Volue Lire 45 USLE45.S Ave 4 13 12 8 2 45.75 -36 length 3 6 Pocess capabilit 6 D howanta h.45 44.65 45.05 45.25 45.45 45.65

1a) This process is not acceptable as lower specified limits are under control but Upper specified limits are out of control .

Acceptable USL value is = 45.5

But it goes upto 45.8

1b) to improve processes performance

1 process capability should be increased

2) high precision machineries should be used