Question

USe tne Force Memod OF tne Frume.praw te moment diagram, A and 8 art PI nned. Choose Ay FIS aPPlid to caicura te tne rcactons as tne redondant reacton.L4F at e mid Pont oF CB. AsSume E and I are constant F-K/F+ A TL L-424 BAY=SSS33 ET DeFlec thons B Fan: 42.67

Answer 1

Page- ( Foxce Method- 8 klet 2 Et 2et 4 et Numbe of etemal indeterminoac - Y-3 need to release any Yedundant, According So, Cwe Cne edundant so ¥eleage thi8 to we need to take Aq as Co-ordinate Yedundant and indicote only extexnal koads and ignore M- diagran- Congider Gng eleased redundants in His diaqyam.

paдe-z Вкtt Av A 2pt ^вy Reactione 8x 4 32 ke Axx4~ 8x4x2- 1ОXO -о3 Дu- kk 21K Во, вy - -1| k - dicgram:- Аppliy unit lood along coarindte O and in tis diagvam igлore all еytenmal Soade с K- А А Iunit load Bи Reactiong- Lu - - \ Аy+Boc E о Ax- Bо Ан XA-tx4 -0 Вы — 1

Page3 Man\d diagramg Table Por Bending Monents DC BD A C PONtion aigin 6-2 O 4 mits - 8 4 M ue have, heye Foxe matrix Fleribility mahi delection matiit de to&upport Seltlemens. deflectian matrix due to pan dadg we have, Mmi and E U d d1S=S 二ロ A2.67

Page-ト Mmi dxt 56-8_472 -SSn.32 - So Ea {£°LS.S A2.T 3. 06 K A - Reactiong- Av = \¥.q4K Axx 4 13.06x 4- 8x 4x 2- I0x2 =0 Ax .4k

рaдe 1.94K- (3.06 K 12.06-8xxo .q 4 6325 1.44 2.06 u-1x 2 .76k-e 2.06 ending momert diagram ie So -Ve kt6325H -Ve -ve M76 4.1L