Question

Force Vector Directed along a Line Learning Goal: To find a force's directional components that act along a cable and to find the coordinates of a point on a cable that has a force vector applied to it. Three-dimensional Cartesian force vectors and used throughout engineering mechanics. The generic force vector is represented as follows: F = Fzi + Fyj + Fzk where F is the force vector and Fx, Fy, and Fz are the vector's I, j, and k components, respectively. The force vector has a magnitude F = . The vector's direction is described by a unit vector u, where u = F/F. As shown, a force vector F with a magnitude of c = 15.0lb is applied at point A and is directed toward point C. (Figure 1) The distance a is 9.50ft and the distance b is 9.50ft. What are the I, j, and k components of F? Express your answers numerically in pounds to three significant figures separated by commas. Fx, Fy, Fz = -16.3, -5.99,40 lb My Answers Give Up Review Part Incorrect; Try Again As shown, the cable OA exerts a force on point O of F = Fxi + Fyj + Fzk. (Figure 2) If the cable's length is a. what are the x, y. and z coordinates of A in terms of a. Fx. Fy, Fz and X. where X = ? Express your answers In terms of a, Fx, Fy, Fz and X separated by commas. (x, y, z) = aFz/X, aFy/X, aFz/X My Answers Give Up Review Part Correct A force's line of action is often described by two points, from which you can first establish a position vector and then a unit vector. The force vector directed along this line is the product of the force's magnitude times the unit vector.

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Answer 1