Question

Consider these five values a population: 8,4,2,4, and 7

a.) Determine the mean of the population. Round to one decimal place

b.) Determine the variance of the population.

Answer 1

$\textup{Mean, } \mu = \frac{8+4+2+4+7}{5} = \frac{25}{5}=5$

$\textup{Population Variance, }\sigma ^{2} = \frac{ \sum (X-\mu)^{2} }{N}$

$\sigma ^{2} = \frac{ (8-5)^{2}+(4-5)^2+(2-5)^2+(4-5)^2+(7-5)^2 }{5}$

$\sigma ^{2} = \frac{ 9+1+9+1+4 }{5} =\frac {24}{5} =4.8$