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The position of a 0.290 kg object attached to a spring is described by x =...

The position of a 0.290 kg object attached to a spring is described by
x = (0.250 m) cos(0.325πt)


a) Find the amplitude of the motion.

b) Calculate the spring constant.

c) Calculate the position at t = 0.225 s.

d) Calculate the object's velocity at t = 0.225 s.

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Answer #1

M0-250y x (0.250 m) Cos(b-125Tt A Cas Lst Cay A 0.250M k mu-(0-25)lO 3257) 0-125T K=0302 N/M x(6-250) Cas(0325T X0-225 r 0.24

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