Question

nT5B-RT21: Ropes Pulling Identical Boxes I-Rope Tension Shown below are boxes that are being pulled by ropes along frictionless surfaces, accelerating toward the left. All of the boxes are identical, and the accelerations of the boxes are indicated in each figure Smallest Rank (from largest to smallest) the magnitude of the tension in these ropes. Largest 2 3 4 OR, all of these ropes have the same tension OR. We cannot determine the ranking for the tensions. Please explain your reasoning IS FOR 6-16-2010 NTSB-RT22: Ropes Pulling Boxes Rope Tension Shown below are boxes that are being pulled by ropes along frictionless surfaces, accelerating toward the left. The accelerations of the boxes are the same, and the masses of the boxes are indicated in cach Ayo Smallest Rank (from largest to smallest) the magnitude of the tension in these ropes. Largest 2 3 4 5 6 OR, all of these ropes have the same tension OR. We cannot determine the ranking for the tensions Please explain your reasoning,

Answer 1

Tension Ta is pulling one box with acceleration a.. so TA = ma Tension To is pulling two box with acceleration 2 a.. so TB=(2m) (2 a) = 4ma Tension Tc is pulling one boxes with acceleration 2 a.. so To=mc2a) = 2 ma Tension To is pulling 3 boxes with acceleration 3 a.. so To=(3m) (3a)=ama TE To TE = (mm) (3a) = 6ma TE =(m) (3a) =3 ma Rank (from largest to smallest) the magnitude of the tension in these ropes. Largest i To? Te To TEST TA Smallest E Tension Ta pulls box of mass 3m with acceleration a.. so Ta = 3m*a = 3ma Tension Tb pulls two boxes of mass 2m,m with acceleration a.. so Tb = 3m*a = 3ma Tension Tc pulls box of mass m with acceleration a.. so Tc = m*a = ma Tension Td pulls two boxes of mass 2m,m with acceleration a.. so Td = 3m*a = 3ma Tension Te pulls box of mass 2m with acceleration a.. so Te = 2m*a = 2ma Tension Tf pulls box of mass 2m with acceleration a.. so Tf = 2m*a = 2ma Rank (from largest to smallest) the magnitude of the tension in these ropes. Largest _ _2_ Smallest (Ta = To = Td)>(Te=Tf) > Tc