IF YOU HAVE ANY DOUBTS COMMENT BELOW I WILL BE TTHERE TO HELP YOU..ALL THE BEST..
AS FOR GIVEN DATA..
Joey works at a chocolate store. Starting at time 0, we have the following 4 customer interarrival times (in minutes):
Bill = 8
Tom = 2
Angie = 5
Ursula = 2
Customers are served in alphabetical order (though once you start service, you don’t get displaced by a higher-priority customer).
The 4 customers order the following numbers of chocolate products, respectively: 6 2 3 1
Suppose it takes Joey 3 minutes to prepare each chocolate product. Further suppose that he charges $2/chocolate. Unfortunately, the customers are unruly and each customer causes $0.50 in damage for every minute the customer has to wait in line.
(a) When does the first customer leave?
(b) What is the average number of customers in the system during the first 20 minutes?
(c) How much money will Joey make or lose with the above 4 customers?
EXPLANATION:
Service time of each customer = Number of chocolate products ordered * 3 minutes to prepare each chocholate product
Customers are served in alphabetical order. However, Bill arives the first. So, he is served first. It takes = 6*3 = 18 minutes to complete his order. His service end time = 8+18 = 26 minutes. By this time, the other three customers have also arrived. So, these customers are served in alphabetical order: Angie, Tom, Ursula
FORMULAS:
Customer | Interarrival time | Arrival time | Service start time | Service time | Service end time |
Bill | 8 | =B2 | =C2 | =6*3 | =D2+E2 |
Angie | 5 | =C4+B3 | =MAX(C3,F2) | =3*3 | =D3+E3 |
Tom | 2 | =C2+B4 | =MAX(C4,F3) | =2*3 | =D4+E4 |
Ursula | 2 | =C3+B5 | =MAX(C5,F4) | =1*3 | =D5+E5 |
(a) First customer leaves at 26 minutes
(b)
During the first 20 minutes, Bill is there in system for 20-8 = 12 minutes
Angie is there in system for 20-15 = 5 minutes
Tom is there in system for 20-10 = 10 minutes
Ursula is there in system for 20-17 = 3 minutes
Average number of customers in the system = (12+5+10+3)/20 = 1.5
(c) Revenue earned = (6+2+3+1)*2 = $ 24
Waiting time for each customer = Service start time - Arrival time
Total waiting time = (8-8)+(26-15)+(35-10)+(41-17) = 60 minutes
Total cost of damage due to customer waiting = 60*0.5 = $ 30
Money made or lost with the above 4 customers = Revenue earned - Total damage due to customer waiting
= 24 - 30
= $ - 6 (loss)
I HOPE YOU UNDERSTAND..
PLS RATE THUMBS UP..ITS HELPS ME ALOT..
THANK YOU...!!
Joey works at a interarrival times (in minutes) .chocolate store. Starting at time 0, we have...
can someone explain to me how i solve this question step by step. Question 14 e Joey works at an ice cream shop. Starting at time 0, five customer interarrival times are as follows (in minutes): 3 2 5 2 2 e Customers are served in FIFO (first-in-first-out) fashion. The 5 customers order the following numbers of ice cream products, respectively: 1 6 3 1 4 Suppose it takes Joey 2 minutes to prepare each ice cream product. Further suppose...
can someone explain to me how i solve this question step by step. Question 14 e Joey works at an ice cream shop. Starting at time 0, five customer interarrival times are as follows (in minutes): 3 2 5 2 2 e Customers are served in FIFO (first-in-first-out) fashion. The 5 customers order the following numbers of ice cream products, respectively: 1 6 3 1 4 Suppose it takes Joey 2 minutes to prepare each ice cream product. Further suppose...
Consider a simple queuing system in which customers arrive randomly such that the time between successive arrivals is exponentially distributed with a rate parameter l = 2.8 per minute. The service time, that is the time it takes to serve each customer is also Exponentially distributed with a rate parameter m = 3 per minute. Create a Matlab simulation to model the above queuing system by randomly sampling time between arrivals and service times from the Exponential Distribution. If a...