Question

Problem 5.0 Find the transfer function by using Nodal Analysis for the following circuits: 4 uF 110 kQ (t) 400 kQ 4 HF (a) + w HH 110 k2 600 k2 4 HF 400 k2 4 pF 600 k2 (b)

Answer 1

Solution:

(a)

Non ime amplifia ciraitTheoPAmp is ViA Youl 0k 22 + The 9deal opAmphas Yheire noninyorti minal vially comaded. N cabbes hever =Vin~ ()nd imvodigk- onout fram oPAmp- apin nalyss Youl-Y 22 ap You 22 22 Vou 21t +4pxok Vin 2t 2.043 Or, Hs Ilcnce the transfer function 2+ 2.045 Or, HIs

22 Yaut 2,a k 0.42S 11k s .452.45 ) 255 0 5-45 45 - 2.27S the circuit I The opAmp is configurcd as non invcrting amplicr as From cqI we havc HiS) 6.45t2-45 250x103 x 250A163 0.42 2hS+C25) 3+ 0.42) (512.-27)(1-542) 5435454 2.45 7.463+ 2.7 563s+ 4.54 13.09 s+ 7.24 4 55.635 5h Ience he ransfer funetion 4913.09 s+ 7.24 435.3 4.54 HIS)