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A small ball rolls horizontally off the edge of a tabletop that is1.17 m high. It...

A small ball rolls horizontally off the edge of a tabletop that is1.17 m high. It strikes the floor at a point 1.18 m horizontallyaway from the edge of the table. (a) How long is the ball in theair? (b) What is its speed at the instant it leaves thetable?
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Answer #1
Kinematics:
Y = yo + vyot +(1/2)ayt2
0 = (1.17m) + 0t +(1/2)(-9.81m/s2)t2
t2 = (-1.17m)/(-4.91m/s2)
t2 = 0.238 s2
--------
t = 0.488s
--------
X = xo + vxot +(1/2)axt2
1.18m = 0m + vxo(0.488s) + 0t2
vxo = (1.18m)/(0.488s)
--------
vxo = 2.42 m/s
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I hope this solution was a Lightsaber for you.
Please remember to always be a Physics Jedi.
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