Given A(t) = 1000e^(0.05t)
the time for which investment increases 50%
1.5*1000 = 1000 * e^(0.05t)
ln(1.5) = 0.05t
t = 8.109 years
o05 AC)= 1,000e0 4. Ellen put $1,000 into a new savings account that paid 5% interest...
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