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o05 AC)= 1,000e0 4. Ellen put $1,000 into a new savings account that paid 5% interest per year, compounded continuously. She

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Answer #1

Given A(t) = 1000e^(0.05t)

the time for which investment increases 50%

1.5*1000 = 1000 * e^(0.05t)

ln(1.5) = 0.05t

t = 8.109 years

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