Question
please help explain the nmr below...
hydrolysis of acetanilude was taking place
-WHERE IS THE PEAK AROUND 8PPM COMING FROM AND WHY IS IT BROAD.

-IS THE SMALL PEAK FROM ACETIC ACID

-WHY IS THE INTEGRATION IN THE AROMATIC REGION 7 and not 5?

please label which proton environment is what.
3 e3.210 A (s) 8.51 #H-1 B (m) 7.28 #H-5 di(s) 2.11 #H-3 hi figure out 7 6 5 4 f1 (ppm) 3 2 SH), 2.11 (s, 3H) -1
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Answer #1

The peak around 8 ppm (8.51 ppm, s) is coming from OH of acetic acid (CH3-C(=O)-OH). This peak is broad because of the H-atom is attached to a heteroatom (O).

Yes, the small peak at 8.51 ppm, the singlet, is coming from acetic acid.

The integration in the aromatic region at 7.28 ppm, the multiplet, is 7H because 5 H's belong to the aromatic phenyl ring (C6H5) and 2 H's belong to amine (NH2) group of aniline (C6H5NH2).

The 3 H's at 3.11 ppm, a singlet, corresponds to the methyl group (CH3) of acetic acid (CH3COOH).

Explanation: The hydrolysis of acetanilide (C6H5NHCOCH3) gives aniline (C6H5NH2) and acetic acid (CH3COOH).

i.e. C6H5NHCOCH3 + H2O ----> C6H5NH2 + CH3COOH

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