Ans 4 :
a)
density = mass / volume
0.851 g/mL = m / 0.100 mL
m = 0.0851 g
mol C4H9Cl = mass /molar mass
= 0.0851 g / 92.566 g/mol = 9.19 x 10-4 mol
so mol ethanol will also be 9.19 x 10-4 mol
mass ethanol = mol x molar mass
= 9.19 x 10-4 mol x 46.07 g/mol
= 0.042 grams
b)
Number of mol of C4H9OCH2CH3 formed will be : 9.19 x 10-4 mol
mass of C4H9OCH2CH3 = mol x molar mass
= 9.19 x 10-4 mol x 102.17 g/mol
= 0.094 grams
c)
Number of mol of HCl produced = 9.19 x 10-4 mol
So mass of HCl = mol x molar mass
= 9.19 x 10-4 mol x 36.46 g/mol
= 0.0335 grams
*please solve using dimensional analysis, thank you* 4. When liquid 2-chloro-2-methylpropane, CaHsCl, is added to ethanol...