Question

Consider the following balanced reaction. What mass (in g) ofCO₂ can be formed from 288 mg of O₂? Assumethat there is excess C₃H₇SH present.

C₃H₇SH(l) + 6 O₂(g) → 3CO₂(g) + SO₂(g) + 4 H₂O (g)

Answer 1

288 mg O2 *(1 g/1000mg) *(1mol /32 g O2) *(3 mol CO2 / 6 mol O2)*(44 g/1mol CO2) = 0.198 grams CO2

Answer 2

        The balencedchemical reaction is

                                                     C3H7SH (l) + 6 O2 (g) -------> 3 CO2 (g) + SO2 (g) +4 H2O (g)

                               

       From above reaction whatwe can understand that 6.0 mols of O2   gives 3.0 mols ofCO2 .

         So now 288 mgof O2 formed CO2 is    ------g

               6 mols of O2 means 6*32g   = 192 g

             288 mg of O2 means   288*10^-3 g = 0.288g

         1mol ofCO2 = 44g of CO2

  

                             Theformation of CO2 from 288mg of O2   = [(3*44)/ 6*32] *288*10^-3 g

                                                                                               = (132/192)*0.288 g

                                                                                               = 0.6875*0.288 g

                                                                                               = 0.198 g

                ∴The mass   of CO2 is formed is 0.198g                                                                             

Answer 3