Please show the steps so I can follow along. Ill comment if incorrect.
The equivalent capacitance of the whole system is 1/(1/C + 1/C +
1/C + 1/C + 1/C + 1/C + 1/C + 1/C + 1/C) = 1/(9/C) = C/9
Capacitance has units of Farads or Coulombs/Volt so all we need to
do is divide the amount of charge that moves through the battery
during the charging process by the voltage across the battery, and
that will give the total capacitance of the system:
(3.95x10^-4 C)/(7.85 V) = 5.03x10^-5 C
Now we have the total capacitance of the system, which is equal to
C/9, so to solve for C:
(5.03x10^-5 C) = C/9
C = 4.527x10^-4 F
Please show the steps so I can follow along. Ill comment if incorrect. Nine uncharged capacitors...
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