Question

Eight uncharged capacitors with equal capacitances are combined in series. The combination is connected to a 6.53-V battery, which charges the capacitors. The charging process involves 3.77

Answer 1

Start with the formula Q = CV

3.77 X 10^-4 = (C)(6.53)

C = 5.77 X 10^-5 F

That is the equivalent capacitance of the system. Since the capacitors are in series, we need to apply the formula

1/C_EQ = 1/C₁ + 1/C₂ + 1/C₃ +...

Since all capacitors are equal, we get

1/C_EQ = 8/C

1/(5.77 X 10^-5) = 8/C

C = 4.62 X 10^-4 F which can also be written as 462 μF or even .462 mF