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Please calculate the pH at the equivalence point when 25 ml of 0.10 NH3 is...


Please calculate the pH at the equivalence point when 25 ml of 0.10 NH3 is titrated with 25 mL of a 0.10 M HCl solution (KaNH4+ is 5.6 X 10-10).

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25 mL of 0.10 M ammonia solution completely neutralsies 25 mL of 0.10 M HCl solution to form ammonium chloride

Ammonium chloride provides ammonium ions

Let x M be the change in to reach equilibrium. Prepare an ICE table

Initial concentration (M) 0.050 0.00 0.00
Change in concentration (M) - x + x + x
Equilibrium concentration (M) 0.050 - x x x

The acid dissociation constant

Since acid dissociation constant is very small, approximate 0.050-x to 0.050

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