C6H12O6 --------------> 2C2H5OH + CO2
2 moles of C2H5OH produced from 1 mole of C6H12O6
2*46g of C2H5OH produced from 180g of C6H12O6
124g of C2H5OH produced from = 180*124/(2*46) = 242.6g of C6H12O6
1 mole of C6H12O6 to gives 2 moles of C2H5OH
180g of C6H12O6 to gives 2*46g of C2H5OH
240g of C6H12O6 to gives = 2*46*240/180 = 122.67g of C2H5OH
8.
V = 4/3Pir^3
= 4/3*3.14*(10^-13)^3
= 4.2*10^-9 cm^3
mass = 1.7*10^-24g
density = mass/volume
= 1.7*10^-24/(4.2*10^-39)
= 4.05*10^14g/cm^3
9. E = 193Kj/mole
= 193000J/mole
= 193000/(6.023*10^23)
= 3.2*10^-19J
E = hv
v = E/h
= 3.2*10^-19/(6.625*10^-34)
= 4.83*10^14 sec^-1
10.
N>F>Si>In >>>>answer
everything please 7) Glucose undergoes fermentation at a winery to produce ethanol and carbon dioxide. How...
Fermentation is the process of making wine by converting glucose (C6H12O6) into Ethanol(C2H5OH) and carbon dioxide (CO2). How many grams of carbon dioxide would be formed from 26 grams of glucose?