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everything please
7) Glucose undergoes fermentation at a winery to produce ethanol and carbon dioxide. How many grams of glucose are required t
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Answer #1

C6H12O6 --------------> 2C2H5OH + CO2

2 moles of C2H5OH produced from 1 mole of C6H12O6

2*46g of C2H5OH produced from 180g of C6H12O6

124g of C2H5OH produced from = 180*124/(2*46)   = 242.6g of C6H12O6

1 mole of C6H12O6 to gives 2 moles of C2H5OH

180g of C6H12O6 to gives 2*46g of C2H5OH

240g of C6H12O6 to gives = 2*46*240/180   = 122.67g of C2H5OH

8.

V = 4/3Pir^3

     = 4/3*3.14*(10^-13)^3

     = 4.2*10^-9 cm^3

mass = 1.7*10^-24g

density = mass/volume

              = 1.7*10^-24/(4.2*10^-39)

              = 4.05*10^14g/cm^3

9. E   = 193Kj/mole

      = 193000J/mole

           = 193000/(6.023*10^23)

            = 3.2*10^-19J

E = hv

v   = E/h

     = 3.2*10^-19/(6.625*10^-34)

     = 4.83*10^14 sec^-1

10.

N>F>Si>In >>>>answer

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