In the figure shown, if a=1.0 cm, b=3.0 cm, and I=30 A,what is the magnitude of...

Question

Question

In the figure shown, if a=1.0 cm, b=3.0 cm, and I=30 A,what is the magnitude of the magnetic field at point P?

In the figure shown, if a=1.0 cm, b=3.0 cm, and I=

The solutions says the answer is 3.14*10^-4. Please help and please be detailed

Answer 1

Answer #1

Magnetic field at the centre due to a coil with n turns = μ0 ni/2r

Here n=quarter circle = 1/4 turn

SInce the straight line parts pass through the point F, mag field at F die to the straight parts iz ZERO.

Due to the circular parts it is given as

= μ0ni/2a - μ0ni/2b

= 4pi*10^-7 * 30 * 1/4 * 1/2 ( 1/1 - 1/3) * 10^2

= 10pi * 10^-5

= 3.14*10^-4

Hope you liked my detailed explanation :)

Answer 2

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