In the figure below, a magnetic field of 0.9 Tesla points into the page. A particle...
In the figure below, a magnetic field of 0.9 Tesla points into the
page. A particle of charge -30 nC and mass 0.3 μg is shot into the
field as shown in the figure with a velocity of 0.6 km/s. What is
the radius of the orbit (in meters)? (The radius is a positive
quantity.) Be careful with the powers of 10. Hint: k=kilo, m=milli,
μ=micro, n=nano and the SI units for B-field, charge, mass, length
and time are: tesla (T), coulomb (C), kilogram (kg), meter (m) and
second (s), respectively
Homework Answers
Bqv = mv^2/r
.9(30 x 10^-9)(.6 x 10^3) = ( 3 x 10^-10)(.6 x 10^-3)^2/r
r= 6.667 m
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In the figure below, a magnetic field of 0.9 Tesla points into the
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(1 point) d A particle is shot into a magnetic field region as shown in the figure. If the particle is shot in with a speed of u = 392 m/s has a charge of q = 33.6 uC and a mass of m = 0.3 mg, how strong must the magnetic field be so the particle just misses the right plate, given that the plates are separated by a distance d = 0.16 m? The magnetic field is equal...
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Figure 20.12 region of magnetic field 1 Path of the particle 1) In Figure 20.12, a...
Figure 20.12 region of magnetic field 1 Path of the particle 1) In Figure 20.12, a small particle of charge q =-1.9 x 10-6 C and mass m 3.1 x 10-12 kg has velocity vo 8.1 x 103 m/s as it enters a region of uniform magnetic field. The particle is observed to travel in the semicircular path shown, with radius R 5.0 cm. Calculate the (a) magnitude and (b) direction of the magnetic field in the region.
(1 point) d A particle is shot into a magnetic field region as shown in the figure. If the particle is shot in with a speed of u = 392 m/s has a charge of q = 33.6 uC and a mass of m = 0.3 mg, how strong must the magnetic field be so the particle just misses the right plate, given that the plates are separated by a distance d = 0.16 m? The magnetic field is equal...
3. Circular Motion in a Magnetic Field See Figure 2. A particle of charge +e and mass m is accelerated from rest by a potential difference V. The particle then enters a region of uniform magnetic field B perpendicular to the velocity. The particle will undergo uniform circular motion. It instead, the charge is doubled and the mass is quadrupled, while keeping both the potential difference and strength of the magnetic field the same, i) how does the radius of...
Active Figure Motion of a Charged Particle in a Uniform Magnetic Field The animation below illustrates a charged particle moving in circular motion due to the magnetic force caused by a constant and uniform magnetic field oriented into the page. The blue crosses represent the tails of the magnetic field vectors nstructions: Use the blue sliders to adjust the mass, speed, particle charge and magnetic field magnitude. Change each parameter and observe the eftect on the particle's motion. If the...
Figure 20.12 region of magnetic field 1 Path of the particle 1) In Figure 20.12, a small particle of charge q =-1.9 x 10-6 C and mass m 3.1 x 10-12 kg has velocity vo 8.1 x 103 m/s as it enters a region of uniform magnetic field. The particle is observed to travel in the semicircular path shown, with radius R 5.0 cm. Calculate the (a) magnitude and (b) direction of the magnetic field in the region.
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