Question

help me these pls

Set up the system of equations. Do not solve: 10.) A load of 300N at the origin is supported by three cables hung at A(0,10, 10), B(-4,-6,10), and C(4,-6,10) respectively. Find the ternsion in each of the supporting cables. (о.10,10), бв. 10/2 (-4,-6,10), OC= 2138 (4,-6,10), (0,0-300) 238 Let OA= w= - Ол -[рА\оА, OC, and for equilibrium OA = 0= (0,0,0) ов, ос OB +OC OB C Ocl OB w Now equate components to get the equations

Answer 1

Solution Civen the da ta Load-30ON Fhrec Cable hung A CO, 10, 10 C-41-6, 10) C C4-610 DA-TA let Tension in Tension in Tension C) TB TL Net foxce TA (-4-6, to) +Te (4-61 10) - o,300

-2Te t2c TAS3Tg3TC TA195TR5Tc 38 V38 0300) - TR TC O I TA 3 TR3Tc o T 5Tg +5 Te > 300 v くこ