Question

Can you help with these two?

Ask Your Teacher 6 1 points KatzPSEf1 2.P.047 My Notes + A uniformly accelerating rocket is found to have a velocity of 13.0 m/s when its height is 7.00 m above the ground, and 1.90 s later the rocket is at a height of 55.0 m. What is the magnitude of its acceleration? m/s2 Need Help? Read It Show My Work (optional) +-12 points KatzPSEf1 2.P.061 My Notes +Ask Your T In the movie Star Wars: The Empire Strikes Back, after being told that Darth Vader is his father, Luke Skywalker falls from a ledge in Cloud City (not on the Earth, so the magnitude of the free-fall acceleration is not necessarily 9.81 m/s2). Suppose he falls distance of 54.0 m in 3.5 s. Assuming he starts from rest, answer the fol lowing questions. Use an upward-pointing y axis. (Express your answers in vector form.) (a) What is Luke's velocity 3.5 s after he starts to fall? m/s (b) What is the constant acceleration due to gravity, experienced by Luke, on Cloud City? m/s2 Need Help? Read It

Answer 1

u= 13-0 m}s. initial t = = 1. 90 sech 4 57) hm 48 m h= ut+at ax (90)2 48 = 13xI-90+ 48-24.7 = La x3-61 2. 23.3= 1.805 x a a 23.3 1-g05 a = 12.9 m/2 falls 54 m is 3. 5 ser, star ting forom oust. h=ut + 놀at? ax(3.52 54=0+ 08 2x 54 a = 3.5)2 2.25 8.82 m/s2Anawe(b) velocity after 3.5 Sec V=uTat V =0+ 8.82x3.5 m /sec v30.87 m/sec Ansidena) _ Please Ubvote