Homework Answers
We need to use law of conservation of linear momentum,
Pi=Pf
m1v1i+m2v2i = m1v1f+m2v2f
Along x axis it becomes,
m1v1ix+m2v2ix= m1v1fx+m2v2fx
20*2+12*0 = 20*1*cos30 + 12*v2fx
v2fx = 1.9 m/s
Along x axis it becomes,
m1v1iy+m2v2iy= m1v1fy+m2v2fy
20*0+12*0 = 20*1*sin30 + 12*v2fy
v2fy= -0.83 m/s
β=tan^-1(v2fy/v2fx) = tan^-1(-0.83/1.9) = -23.6 deg
v2fx=v2cosβ
v2=v2fx/cosβ
v2=1.9/cos(-23.6)
v2= 2.07
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