Question

please write a MATLAB code to solve this problem, all parts from a to d have to be solved in matlab. Thank you        u

The 26-in. drum rotates about a horizontal -7.5 rad/sec axis with a constant angular velocity Q 7.5 rad/s. The small block A has no motion relative to the drum surface as it passes the bottom position 0 0. r-13 a) Determine the coefficient of static friction that would result in block slippage at an angular position 0. 180° b) Plot your expression for 00 the minimum required coefficient value min that would allow the block to remain fixed relative to the c) Determine drum throughout a full revolution d) For a friction coefficient slightly less than min, at what angular position 0 would slippage occur?

Answer 1

esoobutal

N mrw+mgcose

$f = \mu N$

=u(mru mgcos0)

Equilibrium

mgsin= (mrw2mgcos

mu = g*sin (q) / (r*w^2+g*cos (q) ) ;%answer for a 6- 8- Q0:pi; AFigure 1 9 File Edit View Insert Iools Desktop Window Help subs (mu, Q); 0 Mu plot (Q,Mu);%answer for b 1 - 2 mu min max (Mu);%answer for c disp ('minimum friction'); disp (vpa (mu_min)); 3 - 0.7 4 5- 0.6 6 e mu min - g*sin (q) /(r*w*2+g*cos (q)) 7- qa solve (e) ; %answer for d 8 0.5 rad2deg (double (qa (2) ) ) ; %selecting real values ql 9- disp ('angle for slippage') 0- disp (ql) 0.4 1 - ommand Window dsa 0.3 minimum friction 0.61592075480960590707212251955952 0.2 angle for slippage 114.59 0.1 0 0.5 1 1.5 2 2.5

Matlab code:

syms q mu;
g = 32.2;
w = 7.5;
r = 13/12;

mu = g*sin(q)/(r*w^2+g*cos(q));%answer for a

Q = 0:pi;

Mu = subs(mu,Q);
plot(Q,Mu);%answer for b

mu_min = max(Mu);%answer for c
disp('minimum friction');
disp(vpa(mu_min));

e = mu_min - g*sin(q)/(r*w^2+g*cos(q));
qa = solve(e);%answer for d
q1 = rad2deg(double(qa(2)));%selecting real values
disp('angle for slippage');
disp(q1)