If 26 V is applied across the whole network of Fig. 19-52,calculate the voltage across each...

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Question

If 26 V is applied across the whole network of Fig. 19-52,calculate the voltage across each...

If 26 V is applied across the whole network of Fig. 19-52,calculate the voltage across each capacitor.

science physics

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Answer 1

Answer #1

Given

capcitance C1 = 3.0 μF=3.0*10^-6F

capacitance C2 = 4.0 μF=4.0*10^-6F

capcitance C3 = 2 μF =2*10^-6F

voltage V = 26V

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capacitance C1 and C2 are connected isseries

the equavalent capacitor Ceq = C1C2 / ( C1 +C2)

= 1.71*10^-6F

Hence charge on the capacitor

Q = Ceq V

= 44.57*10^-6C

voltage across the capacitorC1

V1 = Q /C1

voltage across the capacitorC2

V2 =V- V1

substitute the values for V1 and V2

capacitor C3 is parallel to C1 and C2 so thatvoltage across C3 is 26V

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Answer 2

Answer #2

capacitors C1 and C2 are connected in series:

1/Ceq=1/c_1 +1/c_2
1/Ceq=1/3+1/4
1/Ceq=.5833
Ceq=1.71

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Answer 3

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If 26 V is applied across the whole network of Fig. 19-52,calculate the voltage across each...