The force on a wire carrying 8.75 A is a maximum of 1.28 N when placed...
The force on a wire carrying 8.75 A is a maximum of 1.28 N when placed between the pole faces of a magnet
Homework Answers
force on couductor is F = ilB
here l = 0.555m
i = 8.75 A
F = 1.28 N
so B = F/iL
B = 1.28/( 8.75 *0.555)
B = 0.263 T
force on a wire of lenght L in B field with currect I
F= B I L
1.28 =B * 8.75 *0.555
B=0.263
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