P(non defective)=P(from A and non defective)+P(from B and non defective)+P(from C and non defective)
=(100/450)*(80/100)+(150/450)*(125/150)+(200/450)*(185/200)=390/450
hence 2d) P(both are non defective) =(390/450)*(390/450)=0.751
Question 2: Basic Probability (New) After graduation, you accept a position at an automotive manufacturer. Your...
Question 2: Basic Probability (New) After graduation, you accept a position at an automotive manufacturer. Your company just received a shipment of raw materials of aluminum, stainless steel, and cast iron in three separate boxes A B and C. Box A contains the aluminum parts, box B contains the made stainless steel parts, and box C contains the cast iron parts. Box B contains 150 parts, among which 25 are defective. Box c Box A contains a total of 100...
pleas help me in this do any question you know using National
Electrical Code 2011
Applied Electricity NEC worksheet t hree Copper conductors with THHN insulation run in Electrical A branch-circuit Consther conductors. The conductor terminations are rated for a maximum ure in the area of this installation is not expected to exceed 30C size 8 AWG, the maximum ampacity of the conductors If the conductors for this circuit are permitted A 40 amperes. B. 50 amperes. to be used...